b^2-3b=28

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Solution for b^2-3b=28 equation:


Simplifying
b2 + -3b = 28

Reorder the terms:
-3b + b2 = 28

Solving
-3b + b2 = 28

Solving for variable 'b'.

Reorder the terms:
-28 + -3b + b2 = 28 + -28

Combine like terms: 28 + -28 = 0
-28 + -3b + b2 = 0

Factor a trinomial.
(-4 + -1b)(7 + -1b) = 0

Subproblem 1

Set the factor '(-4 + -1b)' equal to zero and attempt to solve: Simplifying -4 + -1b = 0 Solving -4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1b = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1b = 0 + 4 -1b = 0 + 4 Combine like terms: 0 + 4 = 4 -1b = 4 Divide each side by '-1'. b = -4 Simplifying b = -4

Subproblem 2

Set the factor '(7 + -1b)' equal to zero and attempt to solve: Simplifying 7 + -1b = 0 Solving 7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1b = 0 + -7 -1b = 0 + -7 Combine like terms: 0 + -7 = -7 -1b = -7 Divide each side by '-1'. b = 7 Simplifying b = 7

Solution

b = {-4, 7}

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